275x^2+120x-16=0

Solution for 275x^2+120x-16=0 equation:

275x^2+120x-16=0

a = 275; b = 120; c = -16;
Δ = b2-4ac
Δ = 1202-4·275·(-16)
Δ = 32000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32000}=\sqrt{6400*5}=\sqrt{6400}*\sqrt{5}=80\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-80\sqrt{5}}{2*275}=\frac{-120-80\sqrt{5}}{550}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+80\sqrt{5}}{2*275}=\frac{-120+80\sqrt{5}}{550}
$